mysql8的json操作

insert into myTable (t_id,year,details) values (5,2019,cast('{"haha":[{"u":1,"t":123 }]}' as json))

 SELECT id  FROM myTable where id=4 and json_contains_path(details->'$[*]', 'one','$[*].haha');

 update myTable set details=JSON_ARRAY_APPEND(details,'$[1].haha',cast('{"u":2,"t":999}' as json)) where id=5

新闻名称：mysql8的json操作
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