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完整的直译为java方法是这样的，但是这样写dataLen的值必须小于等于数组长度，不然会出现下标越界的异常
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public int accumulativeVerification(int[] data, int dataLen) {
int sum = 0;
for (int i = 0; i dataLen; i++) {
sum += data[i];
}
return sum;
}
如果是意译（计算int数组的所有数之和），那么java可以这样写
public int accumulativeVerification(int[] data) {
int sum = 0;
for (int i = 0; i data.length; i++) {
sum += data[i];
}
return sum;
}
public class Test {
private int HASH_LOG = 14;
private int HASH_SIZE=(1 HASH_LOG);
private int HASH_MASK=(HASH_SIZE - 1);
public Long flz_hash(Long a){
Long l1 = 2654435769L;
Long index = (a * l1) 32-HASH_LOG;
return index HASH_MASK;
}
public static void main(String[] args) {
Test test = new Test();
long a = 2;
Long index = test.flz_hash(a);
System.out.println(index);
}
}
public class Test{
public staitc void main(String args){
int i,j,k=3;
for(i=0;i4;k=k-1-i,i++)
{
for(j=0;j4+i;j++)
{
if(jk)
System.out.print(" ");
else
{
System.out.print("*");
j++;
}
}
}
k=3;
}
}
保存为Test.java，然后运行javac Test.java和java Test就可以运行了。。
import java.util.Arrays;
import java.util.Scanner;
public class A {
static final int maxn=100000+5;
static long[] a=new long[maxn],t=new long[maxn];
static long ans=0;
static void mymerge(int x,int m,int y) {
int tx=x,tm=m+1;
int k=0;
while(tx=m tm=y) {
if(a[tx]=a[tm])
t[k++]=a[tx++];
else {
ans+=m-tx+1;
a[k++]=a[tm++];
}
}
while(tx=m) t[k++]=a[tx++];
while(tm=y) t[k++]=a[tm++];
for(int i=0;ik;i++)
a[x++]=t[i];
}
static void mergesort(int x,int y) {
if(x==y)return ;
int mid=(x+y)/2;
int xx=x,yy=y;
mergesort(xx,mid);
mergesort(mid+1,yy);
mymerge(xx,mid,yy);
//System.out.println(xx+" "+mid+" "+yy);
}
public static void main(String[] arg) {
int n,k;
Scanner input=new Scanner(System.in);
while(input.hasNext()) {
n=input.nextInt();
k=input.nextInt();
Arrays.fill(a, 0);
Arrays.fill(t, 0);
for(int i=0;in;i++) {
a[i]=input.nextLong();
}
ans=0;
mergesort(0, n-1);
if(kans)
System.out.println("0");
else
System.out.println((ans-k)+"");
}
}
}
package dis;
import java.io.*;
import java.math.*;
public class dis
{
public static void main(String [] s) throws Exception
{
Float a,b,c;
double x2;
double x1;
System.out.println("请输入a, b, c的值");
BufferedReader bReader=new BufferedReader(new InputStreamReader(System.in));
a=Float.parseFloat(bReader.readLine());
b=Float.parseFloat(bReader.readLine());
c=Float.parseFloat(bReader.readLine());
if (b*b - 4*a*c = 0)
System.out.println("输入的系数不对，b2-4ac不大于0！程序退出！");
else
{
x1 = (-b + Math.sqrt(b*b - 4*a*c))/2*a;
x2 = (-b - Math.sqrt(b*b - 4*a*c))/2*a;
System.out.println("x1 = "+ x1);
System.out.println("x2 = "+x2);
}
return;
}
}
unsigned short crc(unsigned char [] crc_pointer,unsigned short data_length)
{
unsigned short k,k0,bit_flag;
unsigned short int_crc=0xffff;
for (k=0;kdata_length;k++)
{
int_crc^=(crc_pointer)[k];
for(k0=0;k08;k0++)
{
bit_flag=int_crc0x0001;
int_crc=1;
if (bit_flag==1)
int_crc^=0xa001;
}
}
return(int_crc);
}