189 8069 5689
也容易，如果是黑白三个颜色加上相同的渐变量，彩色的是起始颜色的三个分量与终止颜色的对应三个分量的差值，再除于相同的份数，就得出三原色各自的步进量。
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窗体上放个图片框试试下面代码：
Private Sub PictureBox1_Paint(ByVal sender As Object, ByVal e As System.Windows.Forms.PaintEventArgs) Handles PictureBox1.Paint
Dim startColor As Color = Color.Red
Dim endColor As Color = Color.Green
Dim s As String = "vb.net 如何使文字能渐变颜色，就是颜色慢慢变淡然后在慢慢恢复？"
Dim Steps As Integer = s.Length \ 2
Dim StepR As Integer = (CInt(endColor.R) - startColor.R) \ Steps
Dim StepG As Integer = (CInt(endColor.G) - startColor.G) \ Steps
Dim StepB As Integer = (CInt(endColor.B) - startColor.B) \ Steps
Dim R As Integer = startColor.R
Dim G As Integer = startColor.G
Dim B As Integer = startColor.B
Dim drawFont As New System.Drawing.Font("Arial", 16)
Dim X As Integer = 50
For i As Integer = 1 To Steps
Dim drawBrush As New SolidBrush(Color.FromArgb(R, G, B))
e.Graphics.DrawString(s.Substring(i - 1, 1), drawFont, drawBrush, X, 50.0)
X += 18
R += StepR
G += StepG
B += StepB
Next
For i As Integer = 1 To Steps
Dim drawBrush As New SolidBrush(Color.FromArgb(R, G, B))
e.Graphics.DrawString(s.Substring(i + Steps - 1, 1), drawFont, drawBrush, X, 50.0)
X += 18
R -= StepR
G -= StepG
B -= StepB
Next
End Sub
Private Sub CheckBox1_CheckedChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles CheckBox1.CheckedChanged
If CheckBox1.Checked = True Then
TextBox1.ForeColor = Color.Red
Else
TextBox1.ForeColor = Color.Black
End If
End Sub
Private Sub CheckBox2_CheckedChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles CheckBox2.CheckedChanged
If CheckBox2.Checked = True Then
TextBox1.BackColor = Color.Yellow
Else
TextBox1.BackColor = Color.White
End If
End Sub
Label控件是没有办法实现多种颜色的文字的，只能用RichTextBox来实现，而且你的自定义格式字符串也没有结尾的，这样很不好，至少也要red红色字/redyellow黄色字/yellow，而且实现也很麻烦的，下面的代码我没有检测正确性，有错误的自己改一改吧
Dim colortag() as string
dim colors() as color
const txt as string="red红色字/redyellow黄色字/yellow"
private sub Form_Load(object sender,eventargs e)handles mybase.load
colortag(0)="red":Colortag(1)="yellow"
colors(0)=color.red:colors(1)=color.yellow
richtextbox1.text=txt
for i as integer=0 to colortag.lenght-1
dim tag as string="" colortag(i) ""
dim endtag as string="/" colortag(i) ""
dim find as integer=1
do
find=instr(find,txt,tag)+tag.lenght
if(find0)then
dim find1 as integer=instr(find,txt,endtag)
richtextbox1.SelectionStart=find
richtextbox1.selectionlenght=find1-find
richtextbox1.selectioncolor=colors(i)
find=find1
else
exit do
end if
loop
next
end sub
1、2和3:你怎么改的,就怎么恢复默认
3:textbox1.font=new
font(
字体
名称，字体大小，
字形
)，字形有加粗常规倾斜
下划线
等几种。