189 8069 5689
Dim a(6, 6) As Integer, i As Integer, ii As Integer
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Private Sub Command1_Click()
For i = 1 To 6
For ii = 1 To 4
a(i, ii) = Int(Rnd * 90 + 10)
Next ii
Next i
For i = 1 To 6
For ii = 1 To 4
Picture1.Print a(i, ii);
Next ii
Picture1.Print ""
Next i
End Sub
Private Sub Command2_Click()
For ii = 1 To 4
For i = 1 To 6
Picture2.Print a(i, ii);
Next i
Picture2.Print
Next ii
End Sub
VB源程序如下：
Option Base 1
Private Sub Command1_Click()
Dim A(5, 5) As Integer, B(5, 5) As Integer
For x = 1 To 5
For y = 1 To 5
A(x, y) = Int(10 + Rnd * 90) '随机产生两位数的整数
Print A(x, y); '输出
Next
Next
For x = 1 To 5
For y = 1 To 5
B(x, y) = A(y, x) '转置
Print B(x, y); '输出
Next
Next
End Sub
程序输出结果如下：
扩展资料：
VB：编写程序，实现如下规律的5*5矩阵存入数组，并输出该数组
Private Sub Command1_Click()
Dim a(1 To 6, 1 To 6) As Integer
For i = 1 To 5
For j = 1 To 5
tmp = 99
If i tmp Then
tmp = i
End If
If j tmp Then
tmp = j
End If
If 6 - i tmp Then
tmp = 6 - i
End If
If 6 - j tmp Then
tmp = 6 - j
End If
a(i, j) = tmp
Next j
Next i
For i = 1 To 5
For j = 1 To 5
Picture1.Print Tab(j * 5); a(i, j);
Next j
Picture1.Print
Next i
End Sub
程序输出结果如下：
Private Sub Form_Click()
Dim n, m, i, j, Matrix(), Cache() As Integer
n = CInt(InputBox("请输入矩阵行数N", "矩阵置换"))
m = CInt(InputBox("请输入矩阵列数M", "矩阵置换"))
ReDim Matrix(n - 1, m - 1)
ReDim Cache(m - 1, n - 1)
'录入
For i = 0 To n - 1
For j = 0 To m - 1
Matrix(i, j) = CInt(InputBox("请输入矩阵项（" (i + 1) "," (j + 1) "）", "矩阵置换"))
Next
Next
'转置
For i = 0 To n - 1
For j = 0 To m - 1
Cache(j, i) = Matrix(i, j)
Next
Next
'输出转置前的矩阵
Print "转置前的矩阵为："
For i = 0 To n - 1
For j = 0 To m - 1
Print Matrix(i, j);
Next
Next
'输出转置后的矩阵
Print "转置后的矩阵为："
For i = 0 To m - 1
For j = 0 To n - 1
Print Cache(i, j);
Next
Next
End Sub