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串口通信最终都是用二进制传输的，你用代码把二进制转化成十六进制就可以了。不需要额外设置。
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把字符串“12341168C5B7”转换为16进制数存为string型
用shuzi=Convert.ToInt32("12341168C5B7",16)
就ok了。
反之用 shuzi.ToString("X")就行了。
给分！！！
12341168C5B7转换成10进制数就是20014839678391。。
而int32的最大值为2,147,483,647。。所以产生错误。
所以要用int64，它的最大值为9,223,372,036,854,775,807。也就是16位十六进制数0X7FFFFFFFFFFFFFFF。
难道还有比F靠后的数？？？？？？
Option Explicit
Dim Jz As Integer, K As Boolean
Private Sub Command1_Click()
Pic.Cls
If K Then Jz = Val(Qtjz.Text)
If Pd(Text1.Text, Jz) Then Pic.Print "选择的进制与数不符": Exit Sub
If Jz = 0 Then Pic.Print "请先输入进制" Else Pic.Print Zh(Text1.Text, Jz)
End Sub
Private Sub Command2_Click()
End
End Sub
Private Sub Frame1_DragDrop(Source As Control, X As Single, Y As Single)
End Sub
Private Sub Option1_Click(Index As Integer)
K = False
Select Case Index
Case 0
Jz = 2
Case 1
Jz = 8
Case 2
Jz = 10
Case 3
Jz = 16
Case 4
K = True
Qtjz.Text = ""
Qtjz.SetFocus
End Select
If Index 4 Then Command1.SetFocus
End Sub
Private Sub Qtjz_Click()
Qtjz.Text = ""
End Sub
Private Sub Text1_Click()
Text1.Text = ""
End Sub
Private Function Zh(a As String, b As Integer) As Integer
Dim c As String, i, d As Integer
a = LCase(a)
For i = 1 To Len(a)
c = Mid(a, Len(a) + 1 - i, 1)
If Asc(c) 96 Then d = Asc(c) - 87 Else d = Val(c)
Zh = Zh + d * b ^ (i - 1)
Next i
End Function
Private Function Pd(a As String, b As Integer) As Boolean
Dim c As String, i, d As Integer
Pd = False
For i = 1 To Len(a)
c = Mid(a, Len(a) + 1 - i, 1)
If Asc(c) 96 Then d = Asc(c) - 87 Else d = Val(c)
If d b - 1 Then Pd = True: Exit Function
Next i
End Function
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
MsgBox(DEC_to_HEX(255))
End Sub
Public Function DEC_to_HEX(ByVal Dec As Long) As String
Dim a As String
DEC_to_HEX = ""
Do While Dec 0
a = CStr(Dec Mod 16)
Select Case a
Case "10" : a = "A"
Case "11" : a = "B"
Case "12" : a = "C"
Case "13" : a = "D"
Case "14" : a = "E"
Case "15" : a = "F"
End Select
DEC_to_HEX = a DEC_to_HEX
Dec = Dec \ 16
Loop
End Function