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#includestdio.h
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#define SIZE 31
void inputCheck(int,int,int);
int leaYear(int);
main()
{
int year,month,day,d1,result,sum=0;
scanf("%d%d%d",year,month,day);
inputCheck(year,month,day);
for(;year1; year--)
{
if((year%4==0 year%100!=0)||(year%400==0))
sum+=366;
else
sum+=365;
}
d1=leaYear(month);
if((year%4==0 year%100!=0) || (year%400==0))
{
result=(sum+d1+day)%7;}
else
{ if(month2)
result=(sum+d1+day-1)%7;
else result=(sum+d1+day)%7;
}
switch(result)
{
case 1:printf("Monday\n");break;
case 2:printf("Tuesday\n");break;
case 3:printf("Wedensday\n");break;
case 4:printf("Thurfay\n");break;
case 5:printf("Friday\n");break;
case 6:printf("Saturday\n");break;
case 7:printf("Sunday\n");break;
}
return 0;
}
int leaYear(int m)
{
int t=0;
for(; m1;m--)
{
switch(m)
{
case 2:
t+=29;
break;
case 4:
case 6:
case 9:
case 11:
t+=30;
break;
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
t+=31;break;
}
}
return t;
}
void inputCheck(int year,int month,int day)
{
if(year0)
printf("input is wrong!\n");
else
{
switch(month)
{
case 2:
if(day28 (!((year%4==0 year%100!=0) || (year%400==0))))
printf("input is wrong!\n");
if(day29 ((year%4==0 year%100!=0) || (year%400==0)))
printf("input is wrong!\n");break;
case 4:
case 6:
case 9:
case 11:
if(day30)
printf("input is wrong!\n");break;
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
if(day31)
printf("input is wrong!\n");
}
}
}
感觉应该加上判断输入数据是否合格的函数，即便没这个要求，我用测试数据1900 1 1试了试，我的结果是星期一，你的错误你来找吧
#includestdio.h
int main()
{
int a,b,c;
scanf("%d,%d",a,b);
c=(a+b)%7;//求模，这个比较方便
switch(c)
{
case 1:
printf("星期一\n");
break;
case 2:
printf("星期二\n");
break;
case 3:
printf("星期三\n");
break;
case 4:
printf("星期四\n");
break;
case 5:
printf("星期五\n");
break;
case 6:
printf("星期六\n");
break;
case 0:
printf("星期天\n");
break;
}
return 0;
}
这个是1984年1月1日是星期日的，你先看看，我再帮你改，最好自己能看懂
#include stdio.h
void main()
{
int year,month,day;
int tempmonth,yearday;
int week,weekday;
unsigned int sum=0;
int tag=0;
printf("输入年、月、日:\n");
scanf("%d %d %d",year,month,day);
tag =( year - 1980 )/4;
sum=(year-1984)*365 + tag;
tempmonth = month - 1;
yearday = 0;
switch(tempmonth)
{
case 12:yearday+=31;
case 11:yearday+=30;
case 10:yearday+=31;
case 9:yearday+=30;
case 8:yearday+=31;
case 7:yearday+=31;
case 6:yearday+=30;
case 5:yearday+=31;
case 4:yearday+=30;
case 3:yearday+=31;
case 2:yearday+=28;
case 1:yearday+=31;
}
yearday = yearday+day;
if ((year-1984)%4==0 month 2)
{
yearday+=1;
}
sum=sum+yearday;
if (year==1984)
{
sum-=1;
}
printf("距1984年1月1日一共有%d天\n",sum);
/*上面是计算输入的日期距1984年1月1日一共经历了多少天*/
weekday = (sum-1) % 7;
week = yearday / 7;
printf("今天是第%d个星期，星期%d",week,weekday);
return ;
}
下面是修改好的，能多给些分嘛？写程序不容易，还有，好好学习，这些不难，就是多花点时间而已
#include stdio.h
void main()
{
int year,month,day;
int tempmonth,yearday;
int week,weekday;
int sum=0;
int tag=0;
printf("输入年、月、日:\n");
scanf("%d %d %d",year,month,day);
tag =( year - 1988 )/4;
printf("tag=%d\n",tag);
sum=(year-1990)*365 + tag;
tempmonth = month - 1;
yearday = 0;
switch(tempmonth)
{
case 12:yearday+=31;
case 11:yearday+=30;
case 10:yearday+=31;
case 9:yearday+=30;
case 8:yearday+=31;
case 7:yearday+=31;
case 6:yearday+=30;
case 5:yearday+=31;
case 4:yearday+=30;
case 3:yearday+=31;
case 2:yearday+=28;
case 1:yearday+=31;
}
yearday = yearday+day;
if ((year-1988)%4==0 month 2)
{
yearday+=1;
}
sum=sum+yearday;
printf("sum=%d\n",sum);
printf("距1990年1月1日一共有%d天\n",sum);
/*上面是计算输入的日期距1990年1月1日一共经历了多少天*/
weekday = (sum-1) % 7+1;
week = yearday / 7;
printf("今天是第%d个星期，星期%d",week,weekday);
return ;
}
y年m月d日，是第几天days啊？计算方法：days=mon[1]+mon[2]+.+mon[m-1]+d;mon[i]是第i个月的天数；同时要注意，mon[2]闰年29，否则28；给出代码吧，虽然这样对你其实么有什么好处、#includeintmain(){intmon[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};inty,m,d,days;intleap,i;scanf("%d%d%d",y,m,d);for(i=1,days=0;i2)days++;printf("days=%d\n",days);}自己读，自己写，经常百度，不好~~~刚才有个单词打错了，sorry、、~~
#includestdio.h
void main()
{
int a;
printf("input a num\n");
scanf("%d",a);
switch(a){
case 0:
printf("星期日\n");
break;
case 1:
printf("星期一\n");
break;
case 2:
printf("星期二\n");
break;
case 3:
printf("星期三\n");
break;
case 4:
printf("星期四\n");
break;
case 5:
printf("星期五\n");
break;
case 6:
printf("星期六\n");
break;
default:
printf("input fail\n");
break;
}
}